Question

Side of a triangle are in the ratio of 12:17:25 and its perimeter is 540cm. Find its area.°​

Answer 1

Answer is in the attachment ....

Answer 2

$\huge{\bigstar{\underline{\underline{\red{\mathfrak{Solution:}}}}}}$

a:b:c

12:17:25

Side = 12x , 17x , 25x

Perimeter = a + b + c

540cm = 12x + 17x +25x

540cm = 54x

540/54 = x

x = 540/54

x = 10

a = 12 × 10 = 120

b = 17 × 10 = 170

c = 25 × 10 = 250

S = 540/2 = 270

$\bf{\blue{\large{Area\: of\: triangle:}}}$

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{270(270 - 120)(270 - 170)(270 - 250)}$

$\sqrt{270 \times 150 \times 100 \times 20}$

$\sqrt{9 \times 30 \times 5 \times 30 \times 10 \times 10 \times 2 \times 10}$

$\sqrt{3 \times 3 \times 30 \times 30 \times 10 \times 10 \times 10}$

$3 \times 30 \times 10 \times 10$

$\huge{\sf{\pink{9000 {cm}^{2}}}}$