side of a triangle are in the ratio of 12:17:25 and its perimeter is 540 cm find its area
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Answered by
4
let the side of the triangle be 12x , 17x and 25x
Perimeter = 540 cm
12x+ 17x+ 25x = 540
54x = 540
x = 540/54
x = 10
sides of the traingle are 120 , 170 and 250
AREA OF A TRIANGLE = 1/2× B×H
= 1/2× 120 × 170
= 10200 cm^2
Perimeter = 540 cm
12x+ 17x+ 25x = 540
54x = 540
x = 540/54
x = 10
sides of the traingle are 120 , 170 and 250
AREA OF A TRIANGLE = 1/2× B×H
= 1/2× 120 × 170
= 10200 cm^2
Answered by
1
sides of triangle = perimeter = it's all sides
let sides be x
12x + 17x + 25x = 540
54x = 540
x = 10 cm
all sides are equal in length
for area we draw median of the triangle
suppose in triangle a,b,c - d is median
then we have bd = cd = 5cm
we use Pythagoras theorm 10 square - 5square we have height 5root 3
area of triangle = 1/2 base into height
1/2 ×10×5root3. your area will be43.30 something
let sides be x
12x + 17x + 25x = 540
54x = 540
x = 10 cm
all sides are equal in length
for area we draw median of the triangle
suppose in triangle a,b,c - d is median
then we have bd = cd = 5cm
we use Pythagoras theorm 10 square - 5square we have height 5root 3
area of triangle = 1/2 base into height
1/2 ×10×5root3. your area will be43.30 something
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