Math, asked by faridamerchant911, 2 months ago

side of a triangle are in the ratio of 12:17:25 and its perimeter is 540 cm find its area​

Answers

Answered by StormEyes
2

Solution!!

The sides of the triangle are given in a ratio. The perimeter of the triangle is also given. We have to find the area of the triangle. To do so, we need to find all the three sides of the triangle.

Let the sides be 12x, 17x and 25x, respectively.

Perimeter of triangle = Sum of all sides

540 cm = 12x + 17x + 25x

540 cm = 54x

540 cm ÷ 54 = x

x = 10 cm

12x = 12 × 10 cm = 120 cm

12x = 12 × 10 cm = 120 cm17x = 17 × 10 cm = 170 cm

12x = 12 × 10 cm = 120 cm17x = 17 × 10 cm = 170 cm25x = 25 × 10 cm = 250 cm

Verification of the sides:-

540 cm = 12x + 17x + 25x

Taking RHS

= 120 cm + 170 cm + 250 cm

= 540 cm

LHS = RHS

Hence, verified

Now that we have the sides of the triangle, let's find out the area. I'll use the Heron's formula.

Semi-perimeter (s) = (a + b + c)/2

Here a, b and c are the sides.

s = 540 cm/2

s = 270 cm

Area = √[s(s-a)(s-b)(s-c)]

Area = √[270(270-120)(270-170)(270-250)]

Area = √[270(150)(100)(20)]

Area = 9000 cm²

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