Question

side of an equilater triangle is
$\sqrt[12]{3}$
then the area is

Answer 1

➡HERE IS YOUR ANSWER⬇

♧♧FORMULA♧♧

Area of an equilateral triangle

$= \frac{ \sqrt{3} }{4} \times {(side)}^{2}$

♧♧SOLUTION♧♧

Given that :

$side \: \: = \: \: \sqrt[12]{3} \: \: units \\ \\ \: \: \: \: \: \: \: \: \: \: \: = {3}^{ \frac{1}{12} } \: \: units$

So, the area of the triangle

$= \frac{ \sqrt{3} }{4} \times {( {3}^{ \frac{1}{12} }) }^{2} \\ \\ = \frac{ \sqrt{3} }{4} \times {3}^{ \frac{1}{6} } \\ \\ = \frac{ {3}^{ \frac{1}{2} } \times {3}^{ \frac{1}{6} } }{4} \\ \\ = \frac{ {3}^{ \frac{2}{3} } }{4} \\ \\ = 0.416 \: \: {unit}^{2}$

⬆HOPE THIS HELPS YOU⬅