Side of the square is increased by 5 if the ratio of the perimeters of the new square and given square is 3:2 find the perimeter of new square
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60
Step-by-step explanation:
let the side of the square be s
and it is increased by 5
so the new length of the side will be s+5
the perimeter of the given square will be 4s
the perimeter of the new square will be 4(s+5)
given 4(s+5)/4s=3/2
cross multiply
4s*3=2*(4s+5)
12s=8s+40
4s=40
s=10
the perimeter of the new square will be 4(s+5)
=4(15)
60
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