Question

side of triangle are 45cm, 39cm and 42cm find its area​

Answer 1

Answer:

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Let a = 42cm , b = 39 cm , c = 45cm

are three sides of a Triangle.

s = ( a + b + c ) /2

= ( 42 + 39 + 45 ) /2

= 126/2

= 63

s - a = 63 - 42 = 21

s - b = 63 - 39 = 24

s - c = 63 - 45 = 18

Therefore ,

By Heron's formula ,

Area of the triangle ,

∆ = √ s( s - a ) ( s - b ) ( s - c )

= √ 63 × 21 × 24 × 18

= √ 9 × 7 × 7 × 3 × 2 × 2 × 6 × 6 × 3

= √ ( 3×3×3×3)×(7×7)×(6×6)×(2×2)

= 3 × 3 × 7 × 6 × 2

= 756 cm²

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Answer 2

Answer:

Given

a = 45cm

b = 39cm

c = 42cm

Formula Used

s = (a+b+c)/2

Step by step explanation

s = (45+39+42)/2

s = 126/2

s = 63

Formula Used

By Heron's Formula,

Area = √{s(s-a)(s-b)(s-c)}

Step by step explanation

Area = √{63(63-45)(63-39)(63-42)}

= √(63×18×24×21)

= √571536

= 756 cm²

Conclusion

The area of the triangle is 756 cm²