side of triangle are in a ratio of 2 : 9:10 and its perimeter is 420cm. find its area
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Answer:
Let sides of △ are=6x,7x and 8x.
Perimeter=6x+7x+8x=21x.
21x=410 x=20.
Sides are 120,140 and 160 m
Area = S(S−A)(S−B)(S−C) [Heron's Formula]
S= 2
120+140+160=210 m
A= 210(210−120)(210−140)(210−160)
=2100
15 sq. m
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