Question

Side qr of triangle pqr to a point s . The bisector of p meets qr at t prove that angle pqr+angleptr=2angleptr

Answer 1

In △PQR,∠PRS=∠PQR+∠QPR [By exterior angle sum property] ....(1)Also,In △PTR,∠PRS=∠PTR+∠TPR [By exterior angle sum property] ...(2)∠PRS=∠PTR+∠TPQ [∵∠TPR=∠TPQ]

Answer 2

Aryanbhatacharya is right. So it doesn't make sense if i answer. Well done mate❤️❤️