Question

Side XV is a median of a ∆XYZ. Prove that XY + XZ +YZ > 2 XV.

Answer 1

Answer:

XY+YV>XV

XZ+VZ>XV

XY+YV>XV+XZ+VZ>XV

XY + XZ +YZ > 2 XV

Step-by-step explanation:

In triangle XYV:

Two sides of a triangle is greater than the third side So,

XY+YV>XV

In triangle XVZ:

Two sides of a triangle is greater than the third side So,

XZ+VZ>XV

Now we and it.

XY+YV>XV+XZ+VZ>XV

There are 2 XV So it will become 2XV.

YV and VZ are one same line so it will become YZ

Now we write these in their places-

XY + XZ +YZ > 2 XV.