Question

sides AB and AC of a triangle ABC are extended to point P abd Q respectively .also ANGLE PBC<ANGLE QCB show that AC>AB

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Answer 1

angle ABC equal to 180 - angle PBC(LP)

angle ACB equal to 180 -angle QCB(LP)

but angle PBC<angle QCB
so angle ACB< angle ABC
AB<AC
we know that angle of opposite sides is Greater then it's opposite side must be greater

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Answer 2

Answer:

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