Question

sides ab and ac of triangle abc a trisected at d and e respectively then triangle ade and trapezium decb have the area in the ratio of​

Answer 1

Answer:

sides ab and ac of triangle abc a trisected at d and e respectively then triangle ade and trapezium decb have the area in the ratio of​ 1:8

Step-by-step explanation:

Let say area of triangle abc = A

ab & ac is trisected at d & e

Δade ≅ Δabc

ad = (1/3)ab & ae = (1/3)ac

Area of similar Triangle ∝ side²

Area of Δade = (1/3)² Area of Δabc

=> Area of Δade = A/9

area of Δade + Area of trapezium decb = Area of Δabc

=> A/9 + Area of trapezium decb = A

=> Area of trapezium bcde = 8A/9

Ratio of area of Δade & Area of trapezium decb =  A/9  : 8A/9

= 1:8