Sides of a quadrilateral field are given by (7x -3) m , (6x -1)m (3x +5)m and (5x +1)m. Find it is a rectangular field or square field if x =2
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Step-by-step explanation:
Given: Sides of a quadrilateral are:
- (7x -3) m , (6x -1)m (3x +5)m and (5x +1)m.
- x=2.
To find: Whether these sides form rectangle or square.
Sides are :
- 7x-3 = 7×2-3 = 14-3=11m.
- 6x-2= 6×2-1=12-1=11m.
- 3x+6 = 3×2+5= 6+5=11m.
- 5x+1= 5×2+1 = 10+1=11m.
Let us consider , A rectangle and a square of sides ABCD.
If it is a rectangle, then opposite sides are equal.
i.e., AB= CD or AD=BC.
If it is square, then all sides are equal.
i.e., AB=BC=CD=DA.
If we look at the sides, then it is clear that all sides are equal.
:: Hence, these sides forms a square of 11m.
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