Sides of a triangle are in the ratio of 12: 17: 25 and its area is 9000cm2. Find its perimeter.
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Let the sides of the triangle be 12x, 17x and 25x
Perimeter of the triangle = 540 cm
∴ 12x + 17x + 25x = 540
⇒ 54x = 540 ⇒ x = 10
Let, a = 12x = 12 x 10 = 120 cm
b = 17x = 17 x 10 = 170 cm
c = 25x = 25 x 10 = 250 cm
s = (a + b + c)/2 = (120 + 170 + 250)/2 = 540/2
= 270 cm
∴Area of triangle = root under (√s(s -a) (s -b)(s -c))
=root under (√270(270 - 120)(270 - 170)(270 - 250))
= root under (√270 x 150 x 100 x 20)
= 100 under root(√27 x 15 x 20)
= 100 x 9 x 5 x 2
= 9000 cm2
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