Question

sides of a triangle are in the ratio of 12 ratio 17 ratio 25 and its perimeter is 540 cm find its area ​

Answer 1

$\huge{\mathfrak{\green{\star{Answer}}}}$

✔ Let the sides of the triangle be 12x, 17x, 25x

$\large{12x+17x+25x=540}$

$\large{54x=540}$

$\large{x=540/54}$

$\large{\implies{x=10}}$

The sides of the triangle are

$12x = 12(10) = 120cm \\ 17x = 17(10) = 170cm \\ 25x = 25(10) = 250cm$

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Answer 2

$\:\: \underline{\underline{\bf{\large\mathfrak\red{~~Solution~~}}}}$

let the sides are 12x,17x and 25x

now ..the perimeter is =540vm

according to the problem..

12x+17x+25x=540

=>54x=540

=>X=10

therefore the sides are ..120,170,250cm

area

$= \sqrt{270(270 - 120)(270 - 170)(270 - 250)} \\ = \sqrt{270 \times 150 \times 100 \times 20} \\ = 9000 \: cm {}^{2}$

$:\: \underline{\underline{\bf{\large\mathfrak{~hope ~this ~help~you~~}}}}$