Sides of a triangular field are 25m, 26m and 29m. With three corners of the field a sheep, a buffalo and horse are tied separately with ropes of 14m each to graze in the field. Find the area of the field which can be grazed by three animals together.
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Required Area = Area of triangle – Area of 3 sectors Area of Triangle = 1/2 x 24 x 7 = 84 m2 Area of three sectors = πr2/360° x (sum of three angles of triangle) = (22 x 7 x 7 x 180°/ 7 x 2 x 2 x 360°) = 77/4 or 19.25 m2 ∴
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