sides of rectangular park are in ratio 3:2.If it's area is 1536 msquare then cost of fencing it at rd 350 metre
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Answered by
1
Let the sides be 3x and 2x
1536m^2 = 3x × 2x
1536m^2 = 6x^2
square root of 1536 = 6x
39.19 = 6x
x = 39.19÷6
x = 6.5m
3x = 3 × 6.5
= 19.5m
2x = 2 × 6.5
= 13m
we have to find the cost of fencing
Perimeter = 2 (13 + 19.5)
= 2 (32.5)
= 65m
1m = Rs 350
65m = 350 × 65
= Rs 22750
-ArjunIsCool
1536m^2 = 3x × 2x
1536m^2 = 6x^2
square root of 1536 = 6x
39.19 = 6x
x = 39.19÷6
x = 6.5m
3x = 3 × 6.5
= 19.5m
2x = 2 × 6.5
= 13m
we have to find the cost of fencing
Perimeter = 2 (13 + 19.5)
= 2 (32.5)
= 65m
1m = Rs 350
65m = 350 × 65
= Rs 22750
-ArjunIsCool
Answered by
21
Answer:
x + 8x/100 = 769
108x/100 = 769
x = 76900/108
x = 712.03
Hope it will be helpful ✌️
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