Question

Sides of triangle are 12and 12 perimeter is 32 find area

Answer 1

Let the congruent sides of the isosceles triangle =a and the base =b.

Given, b=12cm

Perimeter of the triangle =Sum of all sides = a + a + b =32

⇒2a+12=32

On solving, a =10cm

Since the height of the triangle, divides it into two right angled triangles,

a

2

=h

2

+(

2

b

)

2

⇒10

2

=h

2

+6

2

h

2

=100−36=64

h=

64

=8 cm

Area of triangle =

2

1

×base×height=

2

1

×12×8=48 sq cm

solution