Question

The area of the triangle formed by the points A(-1.5, 3), B(6,-2) and C(-3, 4) is (A) 0 (B) 1 (C) 2 (D) 3/2​

Answer 1

ANSWER:- 0

SOLUTION:-

We know that the area of the triangle whose vertices are (x1,y1),(x2,y2), and (x3,y3) is 21∣x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣

Given P(−1.5,3),Q(6,−2) and R(−3,4)

Therefore, area is given by

=21×[(−1.5)(−2−4)+6(4−3)+(−3)(3+2)]

=21×(9+6−15)

 =0