Question

Silver and copper voltameters are connected in parallel with a battery of e.m.f 12 V. In 30 minute 1 g of silver and 1.8 g of copper are liberated. The energy supplied by the battery is [$Z_{Ag}$ = 11.2 × 10⁻⁴ gc⁻¹; $Z_{Cu}$ = 6.6 × 10⁻⁴ gc⁻¹]
(a) 720 J
(b) 2.41 J
(c) 24.12 J
(d) 4.34 × 10⁴ J

Answer 1

$<b>$

Option A is correct

Answer 2

Answer:

(D) 4.34 × 10⁴ J

Explanation:

Voltage of battery = 12V (Given)

Time = 30 min (Given)

Liberation of silver = 1g (Given)

Liberation of copper = 1.8g (Given)

Therefore,

Current in silver voltmeter i1 = m1/z1t1

= 1/(11.2×10−4)×(30×60)

= 0.5A

i2 = m2/z2t2 i2

=1.8(6.6×10−4)×(30×60) = 1.82A

Therefore, the total current given by battery i = i1+i2 = 2.01A

Energy supplied by battery =EiL|W = (12)×(2.01)×(30×60)

= 4.34 × 10⁴J

Thus, the energy supplied by the battery is 4.34 × 10⁴J