Question

Simple interest on a sum of money for 3 years at 11/10% per annum is Rs600. What will be the compound interest on that sum at the same rate for the same period?


Plzzzzzz answer it

Answer 1

Answer:

18788.43

Step-by-step explanation:

P=600*100/3*11/10

=600*100*10/3*11

=18181.81

C.I=18181.81*(1+R/100)³

=18181.81*(1+11/1000)³

=18181.81*(1011/1000)³

=18788.43

Answer 2

Step-by-step explanation:

first of all we know that SI=600

For C.I, We have to get first P

P = 100×S.I/R×T

P= 100×600/11/10×3

P = 60000/33/10

P= 600000/33

P= 18181.81

NOW, We have to find amount

A= P(1+R/100)³

A= 18181.81(1+33/10/100)³

A = 18181.81(1+1.1/100)³

A= 18181.81(101.1/100)³

A= 18181.81(10,33,364.331/1000000)

A= 18788.43

Now, C.I.= A-P

C.I.= 18788.43-18181.81

C.I.= 606.62 (Ans.)

Thank me later