Math, asked by Asha111111, 1 year ago

Simple interest on certain sum of money for 3 year at 5% is 540. If sum earns compound interest for the same time and rate find the total sum received at the end of the period.

Answers

Answered by raisahabkhothp37n1g
19
rate 5/100=1/20
8000
400 400 400
20 20
20
1
1200=540
1=.45
1261*.45=567.45

Asha111111: 8000 from where
raisahabkhothp37n1g: 20 cube
Answered by erinna
25

The total sum received at the end of the period is 4167.45.

Step-by-step explanation:

It is given that simple interest on certain sum of money for 3 year at 5% is 540.

I=540, r=5%=0.05, t=3.

Formula for simple interest

I=P\times r\times t

where, P is principal, r is rate of interest, t is time in years.

Substitute I=540, r=0.05 and t=3 in the above formula.

540=P\times 0.05\times 3

540=0.15P

Divide both sides by 0.15.

\frac{540}{0.15}=P

3600=P

The principal amount is 3600.

Formula for amount after compound interest is

A=P(1+\frac{r}{n})^{nt}

where, P is Principal , r is rate of interest, t is time in year and n is number of times interest compounded per year.

Substitute P=3600, r=0.05, n=1, t=3 in the above formula.

A=3600(1+\frac{0.05}{1})^{1(3)}

A=3600(1.05)^{3}

A=4167.45

Therefore, the total sum received at the end of the period is 4167.45.

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