Question

Simple interest on the sum of money for 3 years at 5% is 1800 what will be compound interest on that sum at the same interest and same time compounded annually​

Answer 1

Question :-

→ Simple interest on the sum of money for 3 years at 5% is 1800 . what will be compound interest on that sum at the same interest and same time compounded annually .

Answer :-

Compound interest is Rs.1891.5

To Find :-

→ Compound interest

Solution :-

$\pink{\mathfrak{ Given}\begin{cases}\sf{ \red{SI = Rs. 1800} \: }\\\sf{ \green{Rate (R) = 5\%}</p><p> \: } \: \\\sf{ \purple{Time (t) = 3 \: }years \: }\end{cases} \: }$

We know that :

$\sf \mapsto \boxed{ \sf\red{SI} = \frac{P \times R \times t }{100}} \\ \\ \\ \to \sf P = \frac{100 \times1800 }{3 \times 5} \\ \\ \to \sf \red{ P = }20 \green{ \times 600} \\ \\ \to \boxed{ \pink{ \sf P = 12000}}$

Therefore ,

$\implies \red{ \boxed{ \sf \green{ Amount = P }{ \bigg ( \blue{1 + \frac{R}{100} }\bigg) }^{t} }} \\ \\ \mapsto \sf \pink{Amount = 12000 }{ \bigg(1 + \frac{5}{100} \bigg) }^{3} \\ \\ \mapsto \sf \red{ Amount} = 12000 \pink{ \times \frac{21}{20} }\green{ \times \frac{21}{20} \times }\frac{21}{20} \\ \\ \mapsto \sf \green{ Amount = } \frac{3 \times \purple{21 \times 21 \times 21}}{2} \\ \\ \mapsto \boxed{ \sf \pink{ Amount = }Rs. \: 13891.5}$

Hence , Compound interest is -

→ 13891.5 - 12000

→ 1891.5

→ Compound interest is Rs.1891.5

Answer 2

Step-by-step explanation:

S.I=1800

T=3 yrs

R=5

A.T.Q

S.I =P×R×T÷100

1800=P×5×3÷100

1800×100=P×15

180000÷15=P

P=12000

C.I=P{(1+R÷100)^T -1}

C.I=12000{(1+5÷100)^3 -1}

C.I=12000{(105÷100)^3 -1}

C.I=12000{1157625÷1000000 -1}

C.I=12000×157625÷1000000

C.I=1892