Question

simple pendulum completes one vibration in one second if g is equal to 981 metre per second square its length will be​

Answer 1

Thus the length of the pendulum is 0.78 m

Explanation:

Given data:

• Time of vibration = 1 second
• Value of "g" = 9.81 m/s
• Length "L" = ?

Solution:

T = 2 π √ l / g

Taking square root on both sides:

T^2 = 4 π x l / g

(1)^2 = 4 x 22 / 7 x L / 9.81

9.81 x 7 =  4 x 22 x L

L = 9.81 x 7 / 4 x 22

L = 68.67 / 88

L = 0.78 m

Thus the length of the pendulum is 0.78 m