Question

simplfy my question plz
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Answer 1

Hey, here is your answer

Hope it helps you ❤

Here, (a²-b²) +(b²-c²) +(c²-a²)

=a²-b²+b²-c²+c²-a²

=0

Therefore, (a²-b²) ³+(b²-c²) ³+(c²-a²)³=3(a²-b²) (b³-c²) (c²-a²)

=3(a-b) (a+b) (b-c) (b+c) (c-a) (c+a)

Similarly,

(a-b)³+(b-a)³+(c-a)³=3(a-b) (b-c) (c-a)

Thus, (a²-b²)³+(b²-c²) ³+(c²-a²) ³/(a-b)³+(b-c)³+(c-a)³

=>3(a-b) (a+b) (b-c) (b+c) (c-a) (c+a) / 3(a-b) (b-c) (c-a)

=>(a+b) (b+c) (c+a)

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Answer 2

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