Question

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Answer 1

Answer:

a^2b=40,11.

two answers are their.....

Step-by-step explanation:

(3a^2b-8) (a^2b+5)=?

first open the brackets :-

3a^4b^2+15a^2b-8a^2b-40

3a^4b^2+7a^2b-40

3a^4b^2+7a^2b=40

a^2b(3a^2b+7)=40

a^2b=40 ,and,

3a^b+7=40

3a^2b=33

a^2b=11.

hence, answers is 40 ,and, 11.

Answer 2

Simplify:

Step-by-step explanation:

$\ Given \ that:\\\\(3a^2b-8)(a^2b+5)\\\\\ Solve:$

$\rightarrow 3a^2b \times a^2b+3a^2b \times5-8\times a^2b -8\times5=0\\\\\rightarrow 3a^4b^2+ 15a^2b-8a^2b-40=0$

$\rightarrow 3a^4b^2+ 7a^2b-40=0\\\\\rightarrow 3a^4b^2+ 7a^2b=40$

$\rightarrow a^2b (3a^2b+7)=40$

$\rightarrow a^2b=40 \ \ and \ 3a^2b+7=40$

$\rightarrow a^2b=40 \ \ and \ 3a^2b=40-7\\\\\rightarrow a^2b=40 \ \ and \ 3a^2b=33\\\\\rightarrow a^2b=40 \ \ and \ a^2b=\frac{33}{3}\\\\\rightarrow a^2b=40 \ \ and \ a^2b=11$

$\ After \ solve \ value \ is = 40 \ and \ 11$

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