Simplify (1 - cos 0) (1 +cose) (1 + cote).
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Answered by
0
Answer:
Step-by-step explanation:
Expand the brackets using FOIL , or the method you use.
⇒(1+cosx)(1−cosx)=1−cosx+cosx−cos2x
=1−cos2x
using the identity ∣∣
∣∣¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯aasin2x+cos2x=1aa∣∣−−−−−−−−−−−−−−−−−−−−
then 1−cos2x=sin2x
Answered by
3
Answer:
hey here is your answer.
Step-by-step explanation:
(1-cosx) (1+cosx) (1+cotx)
by solving the bracket, we get [cotx = cosx/sinx]
= (1-cosx+cosx-cos^2x) (1+cosx/sinx)
= (1-cos^2x) [(sinx+cosx)/sinx] [1-cos^2x = sin^2x]
= (sin^2x) [(sinx+cosx)/sinx]
= sinx ( sinx + cosx )
= sin^2x + sinx.cosx
hope it help you and please mark it as brainliest.
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