Question

simplify 1-cos theta+ sin theta/ 1+cos theta +sin theta=tan theta/2

Answer 1

LHS=[math]\tan\theta\frac{\sin\theta}{1-\ cos\theta}[/math]= [math]\tan\theta\frac{\ sin\theta(1+\cos\theta)}{\sin^2\theta}[/ math] (by multiplying and ...

Answer 2

QUESTION:

(sinθ + cosθ)² + (sinθ - cosθ)²

FORMULAS USED:

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

sin²θ + cos²θ = 1

ANSWER:

= (sin²θ + cos²θ + 2sinθcosθ) + (sin²θ + cos²θ -2sinθcosθ)

= (1 + 2sinθcosθ) + (1 - 2sinθcosθ)

= 1 + 2sinθcosθ + 1 - 2sinθcosθ

= 2

CONCEPT’s USED:

→» trigonometric identities

→» trigonometric ratios of allied angles

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