Question

Simplify 11x^2 (9x^3 – 19) + 3 and find its value for 
 1) x = 6                       2) x= ¼
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Answer 1

Step-by-step explanation:

If x = 6

• 9x³ + 11x² - 19 + 3
• 9(6)³ + 11(6)² - 16
• 9*216 + 11*36 - 16
• 1944 + 396 - 16
• 2324

If x = ¼

• 9x³ + 11x² - 19 + 3
• 9(¼)³ + 11(¼)² - 16
• 9*$\frac{1}{64}$ + 11*$\frac{1}{16}$ - 16
• 576 + 176 - 16
• 736

Answer 2

Step-by-step explanation:

◗ 　If x = 6

• 9(6) ³ + 11(6) ² - 19 + 3
• 9 × 216 + 11 × 36 - 16
• 1944 + 396 - 16
• 2324

◗ 　If x = ¼

• 9(¼)³ + 11(¼)² - 19 + 3
• 9 × 1/64 + 11 × 1/16 - 16
• 576 + 176 - 16
• 736