Question

The graph between (1)/(v) and (1)/(u) for a concave mirror looks like.

Answer 1

Answer:

straight line

Explanation:

hope the answer will help you

Answer 2

Given :

Concave mirror

To find :

The graph between  $\frac{1}{v}$ and  $\frac{1}{u}$  for given concave mirror

Solution :

Formula for the concave mirror

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$-------(1)

For plotting the graph lets take equation

y = mx + c

where,

m = slope

c = y intercept

Now lets take the equation (1)

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

$\frac{1}{v} = - \frac{1}{u} + \frac{1}{f}$

Here ,

Slope = -1

c = $\frac{1}{f}$

$\frac{1}{f}$ is intercept of y

$\frac{1}{f}$ remains constant when the focal length is equal to infinity but it is zero in this case.

As,

y = definite value  and slope is negative so the graph is linear graph.

Hence , the graph looks like linear graph.