Math, asked by maninder9th, 1 year ago

simplify (1³+2³+3³)½

Answers

Answered by Anonymous
269
hiii!!!

here's Ur answer...

( { {1}^{3} + {2}^{3} + {3}^{3} })^{ \frac{1}{2} } \\ \\ = \: {((1 \times 1 \times 1) + (2 \times 2 \times 2)+ 3 \times (3 \times 3 \times 3))}^{ \frac{1}{2} } \\ \\ = {(1 + 8 + 27)}^{ \frac{1}{2} } \\ \\ = {36}^{ \frac{1}{2} } \\ \\ = {( {2}^{2} \times {3}^{2}) }^{ \frac{1}{2} } \\ \\ = ( {2}^{2 \times \frac{1}{2} } ) \times ( {3}^{2 \times \frac{1}{2} } ) \\ \\ = 2 \times 3 \\ \\ = 6 \\ \\ hope \: this \: helps...

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Answered by smithasijotsl
14

Answer:

(1^3+2^3+3^3)^{\frac{1}{2} }  = 6

Step-by-step explanation:

Required to simply the given expression

(1³+2³+3³)½

Solution:

1³ = 1

2³ = 8

3³ = 27

1³ + 2³+3³ = 1 +8+27 = 36

(1^3+2^3+3^3)^{\frac{1}{2} } = √36  = 6

(1^3+2^3+3^3)^{\frac{1}{2} }  = 6

#SPJ2

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