Simplify [15/3+10{60-8/4+3(5 of 3-7)
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Answered by
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we have to find out the answer through the BODMAS RULE.
B-BRACKET
O-OF
D-DIVISION
M-MULTIPLICATION
A-ADDITION
S-SUBTRACTION
IN CASE OF BRACKETS ,WE HAVE TO OPEN THE BAR FIRST THEN OPEN BRACKET THEN CURLY AND AT LAST RECTANGULAR BRACKET.
SO,ATQ
5 OF 3-7=5×-4= -20.
then ,60-2+3=63-2=》61.
(15/3=5)
Answer= 5+10 {61+3 (-20)
15+{61-60}
15+1= 16
Hope it helps .!!!
B-BRACKET
O-OF
D-DIVISION
M-MULTIPLICATION
A-ADDITION
S-SUBTRACTION
IN CASE OF BRACKETS ,WE HAVE TO OPEN THE BAR FIRST THEN OPEN BRACKET THEN CURLY AND AT LAST RECTANGULAR BRACKET.
SO,ATQ
5 OF 3-7=5×-4= -20.
then ,60-2+3=63-2=》61.
(15/3=5)
Answer= 5+10 {61+3 (-20)
15+{61-60}
15+1= 16
Hope it helps .!!!
M987:
The answer is wrong.
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