Question

simplify:[(2)^-1+(4)^-1+(3)^-1]^-1​

Answer 1

Step-by-step explanation:

15 is the answer I think so

Answer 2

Answer:

$= \left(\left(2\right)^{-1}+\left(4\right)^{-1}+\left(3\right)^{-1}\right)^{-1}\\= \frac{1}{\left(2^{-1}+4^{-1}+3^{-1}\right)}$

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