Question

Simplify ( 2 + √3)2 + ( 2 - √3)2​

Answer 1

Answer:

8

Step-by-step explanation:

(2+_/3)2+(2-_/3)2

= 2 [(2+_/3)+(2-_/3)] {by taking 2 common}

= 2 [2+_/3+2-_/3]

= 2 (4+0)

= 8

or

(2+_/3)2+(2-_/3)2

= 4+2_/3 + 4 -2_/3

= 4+4+2_/3-2_/3

= 8+0

= 8

Answer 2

Answer:

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Step-by-step explanation:

( 2 + √3)2 + ( 2 - √3)2​

We know that

(a+b)^2 = a2+ b2+ 2ab and (a-b)^2 = a2 + b2 - 2ab

{2^2 + (√3)^2 + 2(2)(√3) } + {2^2 + (√3)^2 - 2(2)(√3) }

{4 + 3 + 4 √3} + {4 + 3 - 4 √3}

{7 + 4 √3 } + {7 - 4 √3 }

7 + 4 √3 + 7 - 4 √3

Cancelling 4 √3

7+7 = 14