simplify (2/3)^3×(2/3)^4÷(2/3)^2
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(2/3)^3×(2/3)^4÷(2/3)^2
=(2/3)^(3+4-2)
=(2/3)^5
=(2/3)^(3+4-2)
=(2/3)^5
futureflame43:
tnx
Answered by
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(2/3)^3 x (2/3)^4 / (2/3)^2
= (2/3)^3+4 / (2/3)^2 [ as (2/3)^3 and (2/3)^4 are multiplied so their exponents will be added ]
= (2/3)^7 / (2/3)^2 [ as (2/3)^7 and (2/3)^2 are divided so their exponents will be subtracted ]
= (2/3)^7-2
= (2/3)^5
Hope this is helpful
Plz mark as brainliest !!
= (2/3)^3+4 / (2/3)^2 [ as (2/3)^3 and (2/3)^4 are multiplied so their exponents will be added ]
= (2/3)^7 / (2/3)^2 [ as (2/3)^7 and (2/3)^2 are divided so their exponents will be subtracted ]
= (2/3)^7-2
= (2/3)^5
Hope this is helpful
Plz mark as brainliest !!
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