Math, asked by faiezkhan6184, 1 year ago

Simplify 2 root 3-root 5 by 2root 2+3 root 3

Answers

Answered by saku554
40
I think this is answer
Attachments:
Answered by utsrashmi014
2

Concept

The elimination of radicals from an algebraic fraction's denominator is known as root rationalization in elementary algebra.

Given

Given that 2 root 3-root 5 by 2root 2+3 root 3

Find

We need to simplify \frac{2\sqrt{3}-3\sqrt{5} }{2\sqrt{2}+3\sqrt{3}  }

Solution

To simplify the given equation we will rationalize the denominator

\frac{2\sqrt{3}-3\sqrt{5} }{2\sqrt{2}+3\sqrt{3}}*\frac{2\sqrt{2}-3\sqrt{3}}{2\sqrt{2}-3\sqrt{3}}

\frac{4\sqrt{6}-18-2\sqrt{10}+3\sqrt{15}}{(2\sqrt{2})^2-(3\sqrt{3})^2}\\  

In denominator we applied a^2-b^2

Now

\frac{4\sqrt{6}-18-2\sqrt{10}+3\sqrt{15}}{8-27}\\\ \frac{18+2\sqrt{10}-4\sqrt{6}-3\sqrt{15}}{19}

Hence the simplification is completed

#SPJ2

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