Question

simplify (2x-1)² -(2x+1)(2-5x)
no irrelevant ans pls
And only if you know​

Answer 1

Answer:

$(2x-1)^{2}$=$4x^{2}$-4x+1  [ ∵ $[a-b]^{2}$=$a^{2}$-2ab+$b^{2}$]

(2x+1)(2-5x)=2x(2-5x)+1(2-5x)=4x-$10x^{2}$+2-5x

Now put these equations acc to question,

$(2x-1)^{2}$-(2x+1)(2-5x)=$4x^{2}$-4x+1-(4x-$10x^{2}$+2-5x)

                                 =$4x^{2}$-4x+1-4x+$10x^{2}$-2+5x

                                 ⇒$14x^{2}$-3x-1

Hope it helps you.

Answer 2

Step-by-step explanation:

(2x-1) square - (2x+1)(2-5x)

$(2x)^{2} + 1^{2} -2(2x)(1) - (2x+1)(2-5x)\\4x^{2} +1 -4x - ( 4x-10x^{2} +2 -5x)$

$\\4x^{2} +1 -4x - 4x+10x^{2} -2 +5x)$

$14x^{2} -3x -1$

Hope it helps