simplify (3-√11) (3+√11) of rs aggarwal
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(3-√11)(3+√11)
#first method
(A-B)(A+B)=A^2-B^2
so, using the identity
we get 3^2-√11^2
9-11
-2 is the answer
#second method
multiply the bracket
we get,
9+3√11-3√11-11
9-11
-2 is the answer
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