Question

simplify : 3√2 + √8 - √50​

Answer 1

||SOLUTION||

$3 \sqrt{2} + \sqrt{8} - \sqrt{50} \\ 3 \sqrt{2} + \sqrt{(4 \times 2)} - \sqrt{(25 \times 2)} \\ 3 \sqrt{2} + \sqrt{( {2}^{2} \times 2) } - \sqrt{ ({5}^{2} \times 2) } \\ 3 \sqrt{2} + 2 \sqrt{2} - 5 \sqrt{2} \\ (3 + 2 - 5) \sqrt{2} \\ 0 \sqrt{2} \\ 0$

Required Value

• $\longmapsto\;\bold{0}$

$\tt{@MrMonarque}$

Hope It Helps You ✌️

Answer 2

Gíνєи :-

Simplify :-

$\sf{3 \sqrt{2} + \sqrt{8} - \sqrt{50} }$

∆иѕωєя :-

$\sf{3 \sqrt{2} + \sqrt{8} - \sqrt{50} }$

• Factor $ 8=2^{2}\times 2$. Rewrite the square root of the product $\sqrt{2^{2}\times 2}$ as the product of square roots $\sqrt{2^{2}}\sqrt{2}$. Take the square root of $2^{2}$.

$\leadsto \sf{3\sqrt{2}+2\sqrt{2}-\sqrt{50} }$

• Combine $ 3\sqrt{2} $ and $ 2\sqrt{2}$ to get $ 5\sqrt{2}$.

$\leadsto \sf{5\sqrt{2}-\sqrt{50} }$

• Factor $50=5^{2}\times 2$. Rewrite the square root of the product $\sqrt{5^{2}\times 2} $ as the product of square roots $ \sqrt{5^{2}}\sqrt{2}$. Take the square root of $ 5^{2}$.

$\leadsto \sf{5\sqrt{2}-5\sqrt{2} }$

• Combine $5\sqrt{2}$ and $ -5\sqrt{2}$ to get 0.

$\implies \bf \red{0}$

∴ Hence, the simplification of the given equation will be resulting to 0.

⠀⠀⠀⠀⠀⠀— llMrCrεεpyll —