simplify. 3 underroot 3 +3
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hope this helps you....
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Answered by
1
Hello friend this is your answer...
3√3+2√27+1/√3
3√3+2√9x3+1/√3
3√3+6√3+1/√3
9√3+1/√3 >. 1
(Now rationalising denominator for 1/√3 we get)
1/√3x√3/√3
√3/(√3)^2
√3/3. >. 2
From 1&2
9√3+√3/3
Lcm of 3&1 is 3
27√3/3+√3/3
28√3/3
Hope it helps...
3√3+2√27+1/√3
3√3+2√9x3+1/√3
3√3+6√3+1/√3
9√3+1/√3 >. 1
(Now rationalising denominator for 1/√3 we get)
1/√3x√3/√3
√3/(√3)^2
√3/3. >. 2
From 1&2
9√3+√3/3
Lcm of 3&1 is 3
27√3/3+√3/3
28√3/3
Hope it helps...
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