Question

Simplify:√32+√48÷√8+√12

Answer 1

Hope it's helpful to u.

Answer 2

Answer:

$\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$

= $2$

Explanation:

Simplification of $\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$

= $\frac{\sqrt{4\times8}+\sqrt{4\times12}}{\sqrt{8}+\sqrt{12}}$

=$\frac{\sqrt{4}\times\sqrt{8}+\sqrt{4}\times\sqrt{12}}{\sqrt{8}+\sqrt{12}}$

Take √4 common, we get

= $\frac{\sqrt{4}(\sqrt{8}+\sqrt{12})}{(\sqrt{8}+\sqrt{12})}$

After cancellation,we get

= $\sqrt{4}$

= $2$

Therefore,

$\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$

= $2$

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