Math, asked by andleeb1804, 1 year ago

Simplify ( 343×343×343_113×113×113)/(343×343+343×113+113×113)

Answers

Answered by Anonymous
25
this is ur required result
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Anonymous: ur welcome
Answered by mysticd
19

Answer:

 Value \: of \:\frac{343\times 343\times 343 - 113\times 113\times 113}{343\times 343+343\times 113+113\times 113}= 220

Step-by-step explanation:

\frac{343\times 343\times 343 - 113\times 113\times 113}{343\times 343+343\times 113+113\times 113}

=\frac{343^{3}-113^{3}}{343^{2}+343\times 113+113^{2}}

 By \: algebraic \: identity :\\</p><p>a^{3}-b^{3}= (a-b)(a^{2}+ab+b^{2}

 Here , \\a = 343, \: b = 113

= \frac{(343-113)(343^{2}+343\times 113+113^{2})}{(343^{2}+343\times 113+113^{2})}

= 343-113\\=220

Therefore.,

 Value \: of \:\frac{343\times 343\times 343 - 113\times 113\times 113}{343\times 343+343\times 113+113\times 113}= 220

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