Question

simplify[3x-1÷3x]^2 -[3x+1÷3x][3x-1÷3x]​

Answer 1

hope it helped you, just use the indentities

Answer 2

${( \frac{3x}{1} - \frac{1}{3x} ) }^{2} - (3x + \frac{1}{3x} )(3x - \frac{1}{3x} )$

$= 9 {x}^{2} - 6x \times \frac{1}{3x} + \frac{1}{9 {x}^{2} } - (3x + \frac{1}{3x} )(3x - \frac{1}{3x} )$

$= 9 {x}^{2} - 2 + \frac{1}{9 {x}^{2} } - (3x + \frac{1}{3x} )(3x - \frac{1}{3x} )$

$= 9 {x}^{2} - 2 + \frac{1}{9 {x}^{2} } - ( {3x}^{2} ) - {( \frac{1}{3x} )}^{2}$

$= 9 {x}^{2} - 2 + \frac{1}{9 {x}^{2} } - 9 {x}^{2} - \frac{1}{9 { x}^{2} }$

$= - 2$

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