Simplify 4i(3-i)/1+i
and write in the form of a+bi
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Answer:
4i(3-i) /1+I
=12i-4i^2/1+i
=12i+4/1+I
=(12i+4) (1-i) /(1+I) (1-i)
=12i+12+4-4i/2
=8i+16/2
=4i+8
=8+4i
where a=8 and b=4.
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