Math, asked by uwesh, 1 year ago

simplify √5+√3÷√80+√48-√45-√27

Answers

Answered by YASH3100
205
(√5+√3)/(√80+√48-√45-√27)
=> (√5+√3)/(4√5 + 4√3 - 3√5 - 3√3)
=> (√5+√3)/[4(√5+√3) - 3(√5+√3)]
=> (√5+√3)/[(4-3)*(√5+√3)]
=> 1/(4-3)
=> 1/1
=> 1 ( answer )


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Answered by pinakimandal53
42
FULL ANSWER WITH STEPS

\sqrt{5}+\frac{\sqrt{3}}{\sqrt{80}}+\sqrt{48}-\sqrt{45}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{\sqrt{2*2*2*2*5}}+\sqrt{48}-\sqrt{45}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{\sqrt{2^{4}*5}}+\sqrt{48}-\sqrt{45}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{2^{2}*\sqrt{5}}+\sqrt{48}-\sqrt{45}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+\sqrt{48}-\sqrt{45}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+\sqrt{2*2*2*2*3}-\sqrt{45}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+\sqrt{2^{4}*3}-\sqrt{45}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+2^{2}*\sqrt{3}-\sqrt{45}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+4\sqrt{3}-\sqrt{45}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+4\sqrt{3}-\sqrt{3*3*5}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+4\sqrt{3}-\sqrt{3^{2}*5}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+4\sqrt{3}-3^{1}*\sqrt{5}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+4\sqrt{3}-3\sqrt{5}-\sqrt{27}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+4\sqrt{3}-3\sqrt{5}-\sqrt{3*3*3}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+4\sqrt{3}-3\sqrt{5}-\sqrt{3^{2}*3}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+4\sqrt{3}-3\sqrt{5}-3^{1}*\sqrt{3}
=\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+4\sqrt{3}-3\sqrt{5}-3\sqrt{3}
=\sqrt{5}-3\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+4\sqrt{3}-3\sqrt{3}
=-2\sqrt{5}+\frac{\sqrt{3}}{4\sqrt{5}}+\sqrt{3}
=\frac{\sqrt{3}}{4\sqrt{5}}-2\sqrt{5}+\sqrt{3}
=\frac{\sqrt{3}*\sqrt{5}}{4\sqrt{5}*\sqrt{5}}-2\sqrt{5}+\sqrt{3}
=\frac{\sqrt{3*5}}{4*\sqrt{5}*\sqrt{5}}-2\sqrt{5}+\sqrt{3}
=\frac{\sqrt{15}}{4*5}-2\sqrt{5}+\sqrt{3}
=\frac{\sqrt{15}}{20}-2\sqrt{5}+\sqrt{3}

Here's your answer !!!

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