Question

Simplify: 5(ab-3) + 3ab and find the value of expression when a=1, b=0.

Answer 1

$\huge\underline\mathtt{Your\:Answer}$

= $\mathtt{5(ab-3)+3ab)}$

• Firstly, let's simplify it.

= $\mathtt{5ab-15+3ab}$

• Put a = 1 , b = 0

= $\mathtt{5(1)(0)-15+3(1)(0)}$

= $\mathtt{0-15+0}$

= $\mathtt{-15}$

$\mathtt{\therefore The\:answer\:is\:-15}$

Thank You!!

Answer 2

ANSWER :-

5(ab - 3) + 3ab

putting the values as a=1 , b=0

= 5(1 × 0 – 3) + 3 × 1 × 0

= -15 + 0

= -15

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