English, asked by Aryan1004, 11 months ago

Simplify 5√x 4 4√x3 3√x 2 2√x ​

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Answered by stefangonzalez246
16

\sqrt[5]{x^4\sqrt[4]{x^3\sqrt[3]{x^2\sqrt[2]{x} } } } = x

Explanation:

Given question is incorrect. The correct question is \sqrt[5]{x^4\sqrt[4]{x^3\sqrt[3]{x^2\sqrt[2]{x^2} } } }  

                                    =\sqrt[5]{x^4\sqrt[4]{x^3\sqrt[3]{x^2\sqrt[2]{x^2} } } }

Square root of x² is x,

                                    =\sqrt[5]{x^4\sqrt[4]{x^3\sqrt[]{x^2\times x } } }

when the x is multiplied with x² it gives x³

                                    =\sqrt[5]{x^4\sqrt[4]{x^3\sqrt[]{x^3\ } } }

the cube root of x³ is x,

                                    =\sqrt[5]{x^4\sqrt[4]{x^3\times x } } }

when x is multiplied with x³ it gives x^4

                                     =\sqrt[5]{x^4\sqrt[4]{x^4 } } }  

the fourth root of x^4 is x

                                     = \sqrt[5]{x^4\times x } } }

when the x is multiplied with x^4 it gives x^5

                                      = \sqrt[5]{x^5 } } }

the fifth root of x^5 is x

                                     = x  

\sqrt[5]{x^4\sqrt[4]{x^3\sqrt[3]{x^2\sqrt[2]{x^2} } } }        = x

To learn more...

1. https://brainly.in/question/3790793

2. https://brainly.in/question/11826700

Answered by thakralrishit
9

Answer:

This sum in solved in attached picture, Please refer the same.

Regards,

Rishit Thakral

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