Math, asked by harisri17, 10 months ago

simplify 5t3 / 4t-8*6t-12/10t​

Answers

Answered by thamizhan12341234
0

Answer:

Step-by-step explanation:

 t • (25t3 - 984)

 ————————————————

        20        

Step by step solution :

Step  1  :

           6

Simplify   —

           5

Equation at the end of step  1  :

      (t3)           6

 (((5•————)•t)-48t)-(—•t)

       4             5

Step  2  :

           t3

Simplify   ——

           4  

Equation at the end of step  2  :

        t3                  6t

 (((5 • ——) • t) -  48t) -  ——

        4                   5  

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  4  as the denominator :

          48t     48t • 4

   48t =  ———  =  ———————

           1         4    

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

5t4 - (48t • 4)     5t4 - 192t

———————————————  =  ——————————

       4                4      

Equation at the end of step  3  :

 (5t4 - 192t)    6t

 ———————————— -  ——

      4          5  

Step  4  :

Step  5  :

Pulling out like terms :

5.1     Pull out like factors :

  5t4 - 192t  =   t • (5t3 - 192)  

Trying to factor as a Difference of Cubes:

5.2      Factoring:  5t3 - 192  

Theory : A difference of two perfect cubes,  a3 - b3 can be factored into

             (a-b) • (a2 +ab +b2)

Proof :  (a-b)•(a2+ab+b2) =

           a3+a2b+ab2-ba2-b2a-b3 =

           a3+(a2b-ba2)+(ab2-b2a)-b3 =

           a3+0+0+b3 =

           a3+b3

Check :  5  is not a cube !!

Ruling : Binomial can not be factored as the difference of two perfect cubes

Polynomial Roots Calculator :

5.3    Find roots (zeroes) of :       F(t) = 5t3 - 192

Polynomial Roots Calculator is a set of methods aimed at finding values of  t  for which   F(t)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  t  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  5  and the Trailing Constant is  -192.

The factor(s) are:

of the Leading Coefficient :  1,5

of the Trailing Constant :  1 ,2 ,3 ,4 ,6 ,8 ,12 ,16 ,24 ,32 , etc

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -197.00      

     -1       5        -0.20        -192.04      

     -2       1        -2.00        -232.00      

     -2       5        -0.40        -192.32      

     -3       1        -3.00        -327.00      

Note - For tidiness, printing of 35 checks which found no root was suppressed

Polynomial Roots Calculator found no rational roots

Calculating the Least Common Multiple :

5.4    Find the Least Common Multiple

     The left denominator is :       4  

     The right denominator is :       5  

       Number of times each prime factor

       appears in the factorization of:

Prime  

Factor   Left  

Denominator   Right  

Denominator   L.C.M = Max  

{Left,Right}  

2 2 0 2

5 0 1 1

Product of all  

Prime Factors  4 5 20

     Least Common Multiple:

     20  

Calculating Multipliers :

5.5    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 4

Making Equivalent Fractions :

5.6      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      t • (5t3-192) • 5

  ——————————————————  =   —————————————————

        L.C.M                    20        

  R. Mult. • R. Num.      6t • 4

  ——————————————————  =   ——————

        L.C.M               20  

Adding fractions that have a common denominator :

5.7       Adding up the two equivalent fractions

t • (5t3-192) • 5 - (6t • 4)     25t4 - 984t

————————————————————————————  =  ———————————

             20                      20      

Step  6  :

Pulling out like terms :

6.1     Pull out like factors :

  25t4 - 984t  =   t • (25t3 - 984)  

Trying to factor as a Difference of Cubes:

6.2      Factoring:  25t3 - 984  

Check :  25  is not a cube !!

Ruling : Binomial can not be factored as the difference of two perfect cubes

Polynomial Roots Calculator :

6.3    Find roots (zeroes) of :       F(t) = 25t3 - 984

    See theory in step 5.3

In this case, the Leading Coefficient is  25  and the Trailing Constant is  -984.

The factor(s) are:

of the Leading Coefficient :  1,5 ,25

of the Trailing Constant :  1 ,2 ,3 ,4 ,6 ,8 ,12 ,24 ,41 ,82 , etc

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00       -1009.00      

     -1       5        -0.20        -984.20      

     -1       25        -0.04        -984.00      

     -2       1        -2.00       -1184.00      

     -2       5        -0.40        -985.60      

Note - For tidiness, printing of 55 checks which found no root was suppressed

Polynomial Roots Calculator found no rational roots

Final result :

 t • (25t3 - 984)

 ————————————————

        20        

Processing ends successfully

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