Simplify: √6/√2+√3 + 3√2/√6+√3 - 4√3/√6+√2
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Solution is in theAttachment.
First rationalize the denominator of each term by multiplying its conjugate in both the numerator and denominator and simplify it.
Conjugate of a first term (√2+√3) is
(√2-√3)
Conjugate of second term (√6+√3) is (√6-√3)
Conjugate of third term (√6+√2) is (√6-√2)
In denominator FORMULA used=
(a+b)(a-b)= a² - b²
=========================================================°======
First rationalize the denominator of each term by multiplying its conjugate in both the numerator and denominator and simplify it.
Conjugate of a first term (√2+√3) is
(√2-√3)
Conjugate of second term (√6+√3) is (√6-√3)
Conjugate of third term (√6+√2) is (√6-√2)
In denominator FORMULA used=
(a+b)(a-b)= a² - b²
=========================================================°======
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