Math, asked by mehak2209, 9 months ago

simplify 6 minus 4 root 3 upon 6 + 4 root 3 by rationalizing the denominator​

Answers

Answered by venkatavineela3
1

Answer:

Step-by-step explanation:

6-4root3/6+4root3

rationalising the denominator

the Rationalising factor for 6+4root3 is 6-4root3

now

(6-4root3)(6-4root3)/(6^2-(4root3)^2)

(6-4root3)^2/(36-48)

36+48-48root3/-12

84-48root3/-12

4root3-7

Answered by irshadsyed281
3

\large\bold{\mathcal{Question:}}

\large\bold{\frac{6\:-\:4{\sqrt{3}}}{6\:+\:4{\sqrt{3}}}

\large\bold{\frac{6\:-\:4{\sqrt{3}}\:*\:6\:-\:4{\sqrt{3}}}{6\:+\:4{\sqrt{3}}\:*\:6\:-\:4{\sqrt{3}}}

\large\bold{\frac{6}^2\:+\:{4{\sqrt{3}}^2\:-\:2\:*\4{\sqrt3})}}{6\:-\:4}

Similar questions