simplify: 9-2√3x-x^2÷3-x^2
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Answered by
66
Hi ,
( 9 - 2√3x - x² ) / ( 3 - x² )
= [ 9 - 3√3x + √3x - x² ]/[ (√3)² - x² ]
= [3√3(√3-x)+x(√3- x )]/[((√3+x)(√3-x)]
= [ (√3 - x ) ( 3√3 + x ) ]/[(√3+x)(√3-x)]
After cancellation ,
= ( 3√3 + x )/ ( √3 + x )
I hope this helps you.
: )
( 9 - 2√3x - x² ) / ( 3 - x² )
= [ 9 - 3√3x + √3x - x² ]/[ (√3)² - x² ]
= [3√3(√3-x)+x(√3- x )]/[((√3+x)(√3-x)]
= [ (√3 - x ) ( 3√3 + x ) ]/[(√3+x)(√3-x)]
After cancellation ,
= ( 3√3 + x )/ ( √3 + x )
I hope this helps you.
: )
Answered by
35
Hi,
Please see the attached file!
Thanks
Please see the attached file!
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